A machine gun fires a bullet of mass m with a velocity of 1000 m/min. The man holding the gun can exert a force of 200 N on the gun. The product of mass of each bullet and the number of bullets fired in one sec is

Step-by-step solution

Velocity of the bullet, v = 1000 m/min = 1000 60 m/s = 50 3 m/s Force exerted by the man, F = 200 N The force required to hold the gun is equal to the rate of change of momentum of the bullets. F = n m v where n is the number of bullets fired per second and m is the mass of each bullet. We need to find the product n m . n m = F v Substituting the given values: n m = 200 50 3 = 200 3 50 = 12 kg/s The product of the mass of each bullet and the number of bullets fired in one second is 12 . Answer: 12