What is the ratio of de Broglie wavelength of an electron to that of proton if the velocity of proton is 1 6 the velocity of electron?

Step-by-step solution

The de Broglie wavelength is given by = h mv . For an electron, _e = h m_e v_e . For a proton, _p = h m_p v_p . The ratio of their wavelengths is: _e _p = m_p v_p m_e v_e Given that the velocity of the proton is 1 6 the velocity of the electron, we have v_p = v_e 6 , which gives v_p v_e = 1 6 . The mass of a proton is approximately 1836 times the mass of an electron, so m_p m_e = 1836 . Substituting these values into the ratio: _e _p = 1836 1 6 = 306 The ratio of the de Broglie wavelength of the electron to that of