A plane electromagnetic wave with frequency 40 MHz travels in free space. At a particular point in space and time, the magnetic field is 2 10⁻⁸ T . What will be the electric field at this point?

Step-by-step solution

The relationship between the magnitude of the electric field E and the magnetic field B in an electromagnetic wave traveling in free space is given by E = cB , where c is the speed of light in vacuum. The speed of light in vacuum is c = 3 10⁸ m/s . Given B = 2 10⁻⁸ T , we substitute the values into the equation: E = (3 10⁸ m/s ) (2 10⁻⁸ T ) E = 6 10⁸⁻⁸ V/m E = 6 10⁰ V/m = 6 V/m . Answer: 6 Vm ⁻¹