The height vertically above the earth's surface at which the acceleration due to gravity becomes 1 % of its value at the surface is

Step-by-step solution

Acceleration due to gravity at a height h from the earth's surface, g^ = G M (R+h)^2 Given, g^ =1 % of g= g 100 aligned & g 100 = G M (R+h)^2 & (R+h)^2 100 = G M g or (R+h)^2 100 =R^2 ( g= G M R^2 ) & or aligned R+h & =10 R h & =9 R aligned aligned where, R is the radius of the earth.