Kepler's second law of planetary motion corresponds to

Step-by-step solution

Kepler's second law states that the radius vector joining a planet to the sun sweeps out equal areas in equal intervals of time. The area swept by the radius vector in a small time interval dt is given by dA = 1 2 | r d r | . Since d r = v dt , the rate of area sweeping is dA dt = 1 2 | r v | . Multiplying and dividing by the mass of the planet m , we get dA dt = 1 2m | r m v | = L 2m , where L = r p is the angular momentum of the planet. Since the gravitational force exerted by the sun on the planet is a central f