A current carrying closed loop in the form of a right isosceles triangle XYZ is placed in a uniform magnetic field B acting along X Y of the loop. If the magnetic force on the arm Y Z is 2 F , then the force on the arm X Z is:

Step-by-step solution

The net magnetic force on a closed current-carrying loop in a uniform field is zero: F _ XY + F _ YZ + F _ XZ = 0 Since field B acts along arm XY , the arm XY is parallel to B , so F _ XY = 0 . Therefore: F _ XZ = - F _ YZ = - 2 F