COMEDK2024Morning ShiftPhysicsMagnetic Effects of CurrentActual
A circular coil of radius 0.1 ~m is placed in the X - Y plane and a current 2 ~A is passed through the coil in the clockwise direction when looking from above. Find the magnetic dipole moment of the current loop
Options
- A0.02 Am ^2 in the + ve Z - direction
- B0.02 Am ^2 in the + ve Y - direction
- C0.02 Am ^2 in the -ve X - direction
- D0.02 Am ^2 in the - ve ~Z - direction
Correct answer
D. 0.02 Am ^2 in the - ve ~Z - direction
Step-by-step solution
The magnetic dipole moment m of a current loop is given by the formula m = I A , where I is the current and A is the area vector. The radius of the coil is r = 0.1 m . The area of the circular coil is A = r^2 = (0.1)^2 = 0.01 m ^2 . The current I = 2 A . The magnitude of the magnetic dipole moment is m = I A = 2 0.01 = 0.02 Am ^2 . The coil is placed in the X-Y plane. According to the right-hand rule, for a clockwise current when viewed from above (looking down the positive Z-axis), the direction of the area vector