A straight wire of length 2 ~m carries a current of 10 ~A . If this wire is placed in uniform magnetic field of 0.15 ~T making an angle of 45^ with the magnetic field, the applied force on the wire will be

Step-by-step solution

The force F on a current-carrying wire of length L in a uniform magnetic field B is given by the formula F = I L B ( ) , where I is the current and is the angle between the wire and the magnetic field. Given values are: I = 10 A L = 2 m B = 0.15 T = 45^ Substituting these values into the formula: F = 10 2 0.15 (45^ ) F = 20 0.15 1 2 F = 3 1 2 = 3 2 N Answer: 3 / 2 ~N