COMEDK2020PhysicsMagnetic Effects of Current
An electron moves with speed of 2 10⁵ ~m / s along the positive x -direction in a magnetic field B =( i -4 j -3 k ) T . The magnitude of the force (in N) experienced by the electron is
Options
- A1.18 10⁻¹³
- B1.28 10⁻¹³
- C1.6 10⁻¹³
- D1.72 10⁻¹³
Correct answer
C. 1.6 10⁻¹³
Step-by-step solution
Given, v=2 10⁵ im / s B -( i -4 j -3 k ) T Charge on electron, 4=1.6 10⁻¹⁴ C Foree, F = (v B )=1.6 10⁻¹⁹ [ (2 10⁵ i i -4 j -3 k ]=1.6 10⁻¹⁰ | array ccc i & j & k 2 10⁵ & 0 & 0 1 & -4 & -3 array | P =1.6 10⁻¹⁰ (6 10⁵ j -8 10⁵ k )=9.6 10⁻¹⁴ j -128 10⁻¹⁴ k | F |= (9.6 10⁻¹⁴ )²+ (-128 10⁻¹⁴ )² =10⁻¹⁴ (9.6)³+(126)² -16 10⁻¹⁴ ~N =1.6 10⁻¹³ ~N