COMEDK2015PhysicsMagnetic Effects of Current
A certain length of insulated wire can be bent to form either a single circular loop (case I) or a double loop of smaller radius (case II). When the same steady current is passed through the wire, the ratio of the magnetic field at the centre in (case I) to that in (case II) is
Options
- A1
- B2
- C1 / 2
- D1 / 4
Correct answer
D. 1 / 4
Step-by-step solution
Magnetic field at the centre due to current carrying circular loop having N turns is given as B= ₀ N I 2 r If l be the length of wire, then for the first case, aligned 2 r₁ &=l r₁ &= l 2 Magnetic field, B₁ &= ₀ 1 I 2 r₁ = ₀ I 2 l / 2 B₁ &= ₀ I l ...(i) aligned For the second case, 2 2 r₂=l r₂= l 4 B₂= ₀ 2 I 2 r₂ = 2 ₀ I 2 l 4 B₂= 4 ₀ I l =4 B₁ [from . Eq .( i ) ] B₁ B₂ = 1 4