The relative errors in the measurement of two lengths 1.02 ~cm 0.01 ~cm and 9.89 ~cm 0.01 ~cm is

Step-by-step solution

The relative error in a measurement x x is given by x x . The percentage error is given by x x 100 % . For the first measurement 1.02 0.01 cm , the relative error is 0.01 1.02 . The percentage error is 0.01 1.02 100 % 0.98 % 1 % . For the second measurement 9.89 0.01 cm , the relative error is 0.01 9.89 . The percentage error is 0.01 9.89 100 % 0.101 % 0.1 % . Thus, the relative errors are approximately 1 % and 0.1 % . Answer: 1 % and 0.1 %