COMEDK2014PhysicsMathematics in Physics
Two boys are standing at ends A and B of a ground where A B=200 ~m . The boy at B starts running in a direction perpendicular to A B with a speed of 6 ~ms ⁻¹ . The boy at A starts simultaneously with a velocity of 10 ~ms ⁻¹ and catches the other at time, t where the time, t is
Options
- A50 ~s
- B20 ~s
- C25 ~s
- D12.5 ~s
Correct answer
C. 25 ~s
Step-by-step solution
The given situation is shown below aligned &v_ A =10 ~m / s &v_ B =6 ~m / s aligned The two boys meet at point C after a time t . Horizontal component of velocity of v_ A . aligned v_ A B &=v_ A =10 &=10 ( 10²-6² 10 ) &=8 ~m / s t &= A B v_ A B = 200 8 =25 ~s aligned