What is the relation obeyed by the angles of contact ₁, ₂ and ₃ of 3 liquids of different densities P₁, P₂ and P₃ respectively ( P ₁ < P ₂ < P ₃ ) when they rise to the same capillary height in 3 identical capillaries and having nearly same surface tension T ?

Step-by-step solution

From Jurin's law: h = 2T rPg Since h , T , r , g are constant: P Given P₁ ₁ Since liquids rise ( h > 0 ), > 0 , so all angles are acute: 0 In [0, 2 ) , cosine is decreasing, so smaller cosine means larger angle: ₁ > ₂ > ₃ Combined: 2 > ₁ > ₂ > ₃ 0