Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V . If the length of the capillary is doubled and the diameter of the bore is halved, then the rate of flow would become

Step-by-step solution

Given, V₁=V, l₁=l, r₁=r aligned &l₂=2 l₁=2 l &r₂= r₁ 2 = r 2 &V₂=? aligned According to Poiseuille's formula, the rate of flow of liquid through a narrow tube is given as aligned & V= p r⁴ 8 n l & V r⁴ l & V₂ V₁ = ( r₂ r₁ )⁴ l₁ l₂ aligned aligned &= ( r / 2 r )⁴ ( l 2 l )= ( 1 2 )⁴ 1 2 = 1 32 V₂ &= V₁ 32 = V 32 aligned