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COMEDK202510 May 2025Morning ShiftPhysicsMotion in One DimensionActual

A particle moves towards west with a velocity of 10 ~ms ⁻¹ . After 10s its direction changes towards south and it moves with the same velocity. The average acceleration of the particle is:

Options

  1. A2 m s⁻² S E
  2. B2 2 m s⁻² N E
  3. C( 1 2 ) m s⁻² S E
  4. D2 m s⁻² N E

Correct answer

A. 2 m s⁻² S E

Step-by-step solution

The initial velocity vector is v _i = -10 i m/s (towards west). The final velocity vector is v _f = -10 j m/s (towards south). The change in velocity is v = v _f - v _i = -10 j - (-10 i ) = 10 i - 10 j m/s . The time interval is t = 10 s . The average acceleration is a _ avg = v t = 10 i - 10 j 10 = 1 i - 1 j m/s ^2 . The magnitude of the average acceleration is | a _ avg | = 1^2 + (-1)^2 = 2 m/s ^2 . The direction is given by the vector i - j , which points towards the South-East (SE) direction. Answer: 2 m s⁻² S

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