Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK2016PhysicsMotion in One Dimension

A stone dropped from the top of the tower reaches ground in 4 ~s . Height of the tower is (g=10 ~m / s ² )

Options

  1. A20 ~m
  2. B40 ~m
  3. C60 ~m
  4. D80 ~m

Correct answer

D. 80 ~m

Step-by-step solution

Given, t=4 ~s , u=0, g=10 ~ms ⁻² Using equation of motion, h=u t+ 1 2 g t²= 1 2 g t²= 1 2 10 (4)²=80 ~m

Practice Motion in One Dimension on Quantrex Academy →

More from Motion in One Dimension

An object is dropped from a certain point A at a height 'h' from the ground. During it's journey straight downwards, the object passes points B and C such that the ratio of time ta 2026A particle moves along a parabolic path y = 9x^2 in such a way that the x component of velocity remains constant. If, the acceleration of the particle is 2j ms⁻² , find the x compo 2026A car, starting from rest, accelerates at a rate of through a distance S, then continues at constant speed for time t and then decelerates at a rate of 2 to come to rest. If the to 2026A car covers the first half of the distance between two places at 40 km/h and another half at 50 km/h. The average speed of the car is 2026The velocity of a particle moving along x -axis is given as V = x^2 - 5x + 4 (in m/s) where x denotes the x -coordinate of the particle in metres. The magnitude of the acceleration 2026If the displacement (s in metre) of a moving particle in terms of time (t in second) is s=t^3-6 t^2+18 t+9 , then the minimum velocity attained by the particle is 2025A ball projected vertically upwards with a velocity 'v' passes through a point P in its upward journey in a time of ' x ' seconds. From there, the time in which the ball again pass 2025The displacement (x) and time (t) graph of a particle moving along a straight line is shown in the figure. The average velocity of the particle in the time of 10 s is 2025 Full Motion in One Dimension list All COMEDK PYQs