A body is moving along a circular path of radius ' r ' with a frequency of revolution numerically equal to the radius of the circular path. What is the acceleration of the body if radius of the path is ( 5 ) m ?

Step-by-step solution

The acceleration of a body moving in a circular path is the centripetal acceleration, given by a = ^2 r . The angular velocity is related to the frequency f by the formula = 2 f . Given that the frequency f is numerically equal to the radius r , we have f = r . Substituting f = r into the expression for , we get = 2 r . The acceleration a becomes a = (2 r)^2 r = 4 ^2 r^3 . Given the radius r = 5 m, we substitute this value into the expression for a : a = 4 ^2 ( 5 )^3 a = 4 ^2 ( 125 ^3 ) a = 4 125 = 500 ms ⁻² . Answ