Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK2017PhysicsMotion in Two Dimensions

From the top of a tower, two stones whose masses are in the ratio 1: 2 are thrown-one straight up with an initial speed u and the second straight down with the same speed u . Then, neglecting air resistance

Options

  1. Athe heavier stone hits the ground with a higher speed
  2. Bthe lighter stone hits the ground with a higher speed
  3. CBoth the stones will have the same speed when they hit the ground
  4. Dthe speed can't be determined with the given data

Correct answer

C. Both the stones will have the same speed when they hit the ground

Step-by-step solution

The first stone move up to some height and then its velocity becomes zero. Now, it move downward and at the level of top of tower, it acquires the same initial velocity u and gravitational acceleration g in downward direction. The second stone is moving with the same speed u and with downward acceleration g . So, both will have same final velocity when they reach the bottom and hit the ground.

Practice Motion in Two Dimensions on Quantrex Academy →

More from Motion in Two Dimensions

A boy, standing at a certain height, kicks a football horizontally with a velocity of 19.6 ms⁻¹ . What will be the ratio of horizontal and vertical components of velocities after 2 2026From the same point, two stones A and B are thrown simultaneously, A is thrown up vertically with a velocity of 10 ms⁻¹ and B is thrown up with the same velocity at 30^ with the ho 2026Two bodies are projected with the same velocity. If one is projected at an angle of 30^ and the other at 45^ to the horizontal, then the ratio of maximum heights attained is 2026If two bodies A and B are projected with same velocity but with different angles ₁ and ₂ respectively with the horizontal such that both will have same range, then the ratio of tim 2025If the horizontal range of a body projected with a velocity ' u ' is 3 times the maximum height reached by it, then the range of the body is (g - acceleration due to gravity) 2025If the velocity at the maximum height of a projectile projected at an angle of 45^ is 20 ~m ~s ⁻¹ , then the maximum height reached by the projectile is (Acceleration due to gravit 2025If the range of a body projected with a velocity of 60 ~m ~s ⁻¹ is 180 3 ~m , then the angle of projection of the body is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025If the height of a projectile at a time of 2 s from the beginning of motion is 60 m, then the time of flight of the projectile is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025 Full Motion in Two Dimensions list All COMEDK PYQs