Force constant of interatomic bond, in a certain element, is 7.1 Nm⁻¹ . If the atom oscillates in SHM in a certain direction, what is its frequency? Given: Mole weight of the given element is 108g and Avagadro's number = 6.023 10²³ g mol⁻¹

Step-by-step solution

Mass of a single atom is given by m = M N_A Substituting the given values: m = 108 10⁻³ 6.023 10²³ 1.793 10⁻²⁵ kg The frequency of oscillation of the atom in simple harmonic motion is given by: = 1 2 k m Substituting k = 7.1 N m⁻¹ and m = 1.793 10⁻²⁵ kg : = 1 2 7.1 1.793 10⁻²⁵ = 1 2 39.6 10²⁴ = 6.29 10¹² 2 1 10¹² s⁻¹ Answer: 1 10¹² s⁻¹