The ratio of the angle of deviation produced by a thin prism, when it is placed in air to the angle of deviation produced when it is immersed in water of refractive index 4 3 is:

Step-by-step solution

The angle of deviation produced by a thin prism is given by = ( _ rel - 1)A , where _ rel is the refractive index of the prism relative to the surrounding medium. Assuming the refractive index of the glass prism to be _g = 3 2 . When the prism is in air, the relative refractive index is _g . _ air = ( _g - 1 )A = ( 3 2 - 1 )A = A 2 When the prism is immersed in water, the relative refractive index is _ rel = _g _w . Given _w = 4 3 , we have _ rel = 3/2 4/3 = 9 8 . _ water = ( 9 8 - 1 )A = A 8 The ratio of the angle