The reverse current in the semiconductor diode changes from 20 A to 40 A when the reverse potential is changed from 10 ~V to 15 ~V , then the reverse resistance of the junction diode will be :

Step-by-step solution

The reverse resistance R of a junction diode is defined as the ratio of the change in reverse potential V to the change in reverse current I . Given: Initial potential V₁ = 10 V Final potential V₂ = 15 V Initial current I₁ = 20 A = 20 10⁻⁶ A Final current I₂ = 40 A = 40 10⁻⁶ A Change in potential V = V₂ - V₁ = 15 V - 10 V = 5 V Change in current I = I₂ - I₁ = 40 A - 20 A = 20 A = 20 10⁻⁶ A The reverse resistance R is calculated as: R = V I = 5 V 20 10⁻⁶ A R = 5 20 10⁶ = 0.25 10⁶ = 250 10³ = 250 k Answer: 250 ~k