100 g of ice at 0^ C is mixed with 100 g of water at 80^ C . The final temperature of the mixture is (Given, latent heat of fusion of ice, L_f=80 cal / g and specific heat capacity of water, S_ water =1 cal / g ^ C )

Step-by-step solution

Let the final temperature of mixture be T^ C . From principle of calorimetry, Heat given by 100 g of water = Heat taken by 100 g of ice m₁ S_ water ( T₁ )=m₂ L_f+m₂ S_ water T₂ Substituting the given values, we get aligned & 100 1 (80-T)=100 80+100 1 (T-0) & 80-T=80+T & 2 T=0 T=0^ C aligned