COMEDK2016PhysicsThermal Properties of Matter
Two rods of same area of cross-section and lengths and conductivities K₁ and K₂ are connected in series. Then in steady state, conductivity of the combination is
Options
- A(K₁+K₂ ) / (K₁ K₂ )
- B2 K₁ K₂ / (K₁+K₂ )
- C(K₁+K₂ ) / 2
- DK₁ K₂ / (K₁+K₂ )
Correct answer
B. 2 K₁ K₂ / (K₁+K₂ )
Step-by-step solution
The thermal resistance of a rod is given by R= l K A As, length and area of two rods are same, then in series combination, aligned R &=R₁+R₂ & 2 l K_ s A &= l K₁ A + l K₂ A & 2 K_ s &= 1 K₁ + 1 K₂ = K₁+K₂ K₁ K₂ & K_ s &= 2 K₁ K₂ K₁+K₂ aligned