If a Carnot heat engine has a sink at a temperature of 27^ C and takes 100 kcal of heat from a source at a temperature of 627^ C , the work done (in J) is:

Step-by-step solution

T₂ = 27 + 273 = 300 , K , T₁ = 627 + 273 = 900 , K = 1 - T₂ T₁ = 1 - 300 900 = 2 3 Q₁ = 100 , kcal = 10^5 4.2 , J = 4.2 10^5 , J W = Q₁ = 2 3 4.2 10^5 = 2.8 10^5 = 0.28 10^6 , J Correct option: (1)