An ideal gas is taken through the cycle A B C A , as shown in the figure (assume Volume V is in m^3 ). If the net heat supplied to the gas in the cycle is 5 J, the work done by the gas in the process C A is,

Step-by-step solution

For a complete cycle, U_ net = 0 , so by the first law: W_ net = Q_ net = 5 J W_ net = W_ A B + W_ B C + W_ C A Process A B : Constant pressure p = 10 N/m ^2 , volume increases from V_A = 1 m ^3 to V_B = 2 m ^3 W_ A B = p V = 10 (2-1) = 10 J Process B C : Constant volume ( V = 0 ) W_ B C = 0 J Substituting: 5 = 10 + 0 + W_ C A W_ C A = -5 J