Carnot heat engine takes 300 ~J of heat from a source at 627^ C and gives some part of it to sink at 27^ C . Work done by engine in one cycle is

Step-by-step solution

The efficiency of a Carnot engine is given by =1- T₂ T₁ Given, T₁=627^ C =627+273=900 ~K and T₂=27^ C =27+273=300 ~K =1- 300 900 = 600 900 = 2 3 Also, = Work done Heat taken Work done = Heat taken = 2 3 300=200 ~J