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COMEDK202510 May 2025Evening ShiftPhysicsWave OpticsActual

In the Young's double slit experiment, when a monochromatic light is used, fringe width obtained is 1 mm . If the wave length is halved and the slit width is doubled, what will be the new fringe width?

Options

  1. A1 mm
  2. B0.25 mm
  3. C1.25 mm
  4. D0.5 mm

Correct answer

B. 0.25 mm

Step-by-step solution

The fringe width in Young's double slit experiment is given by the formula = D d , where is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the two slits. Given the initial fringe width ₁ = 1 mm, we have ₁ = ₁ D d₁ = 1 mm. According to the problem, the new wavelength ₂ = ₁ 2 and the new slit separation d₂ = 2d₁ . The distance D remains constant. The new fringe width ₂ is given by ₂ = ₂ D d₂ . Substituting the new values, we get ₂ = ( ₁ / 2) D 2 d₁ = 1 4 ₁ D

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