The wavelength of a monochromatic light which is used in single slit diffraction is 800 nm . The width of the single slit for which the first minimum appears at =45^ on the screen will be:

Step-by-step solution

The condition for the first minimum in single slit diffraction is given by the formula a = n , where a is the width of the slit, is the angle of diffraction, n is the order of the minimum, and is the wavelength of the light. Given values are = 800 nm = 800 10⁻⁹ m and = 45^ . For the first minimum, n = 1 . Substituting these values into the formula: a 45^ = 1 800 10⁻⁹ m a 1 2 = 800 10⁻⁹ m a = 800 2 10⁻⁹ m Using 2 1.414 : a = 800 1.414 10⁻⁹ m a = 1131.2 10⁻⁹ m a = 1.1312 10⁻⁶ m = 1.13 m Answer: 1.13 ~m