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COMEDK202510 May 2025Morning ShiftPhysicsWave OpticsActual

If E is the amplitude of the electric field of the waves starting from the slits in a double slit experiment and is the phase difference between the waves reaching a point on the screen, the ratio of the amplitude of the resultant electric field at that point on the screen to the amplitude at one of the slits is

Options

  1. A2 ( 2 )
  2. B2 ( )
  3. C( 2 )
  4. D( )

Correct answer

A. 2 ( 2 )

Step-by-step solution

Let the electric field of the waves from the two slits be E₁ = E ( t) and E₂ = E ( t + ) , where E is the amplitude of each wave and is the phase difference. The resultant electric field E_R is given by the superposition principle: E_R = E₁ + E₂ = E [ ( t) + ( t + )] . Using the trigonometric identity A + B = 2 ( A+B 2 ) ( A-B 2 ) , we get: E_R = E 2 ( t + 2 ) ( 2 ) . The amplitude of the resultant electric field is the coefficient of the oscillating term, which is 2E ( 2 ) . The ratio of the resultant amplitude to

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