A slit of width 10 10⁻⁷ ~m is illuminated by light of wavelength 500 ~nm . Angular position of the first minimum is

Step-by-step solution

The condition for the first minimum in a single-slit diffraction pattern is given by a = n , where a is the slit width, is the angular position, n is the order of the minimum, and is the wavelength of light. Given values are a = 10 10⁻⁷ m = 10⁻⁶ m , = 500 nm = 500 10⁻⁹ m = 5 10⁻⁷ m , and n = 1 for the first minimum. Substituting these values into the formula: 10⁻⁶ = 1 5 10⁻⁷ = 5 10⁻⁷ 10⁻⁶ = 0.5 Since = 0.5 , the angle is 30^ . Answer: 30 ^