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The width of the fringes obtained in the Young's double slit experiment is 2.6 ~mm when light of wave length 6000^ A is used. If the whole apparatus is immersed in a liquid of refractive index 1.3 the new fringe width will be :

Options

  1. A2.6 mm
  2. B2 mm
  3. C5.2 mm
  4. D4 mm

Correct answer

B. 2 mm

Step-by-step solution

The fringe width in Young's double slit experiment is given by the formula = D d , where is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits. When the apparatus is immersed in a liquid of refractive index , the wavelength of light changes to ' = . The new fringe width ' is given by ' = ' D d = D d = . Given = 2.6 mm and = 1.3 , we have ' = 2.6 1.3 mm = 2 mm . Answer: 2 mm

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