In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is 9: 1 . The ratio of amplitudes of coherent sources is

Step-by-step solution

Assume, Young's double slit experiment, amplitudes corresponding to the sources S₁ and S₂ be a₁ and a₂ and intensities be I₁ and I₂ respectively. So, I_ a_ ^2 and I_ a_ min ^2 I_ I_ = ( a_ a_ )^2= ( a₁+a₂ a₁-a₂ )^2 According to given question, aligned I_ I_ & = 9 1 9 & = ( a₁ / a₂+1 a₁ / a₂-1 )^2 aligned aligned & (3)^2= ( a₁ / a₂+1 a₁ / a₂-1 )^2 (given) & 3= a₁ / a₂+1 a₁ / a₂-1 3= ( a₁+a₂ a₂ ) ( a₁-a₂ a₂ ) 3= a₁+a₂ a₁-a₂ & 3 (a₁-a₂ )=a₁+a₂ 3 a₁-3 a₂=a₁+a₂ & 2 a₁=4 a₂ a₁ a₂ = 4 2 a₁: a₂=2: 1 aligned