A light having wavelength 6400^ A is incident normally on a slit of width 2 ~mm . Then the linear width of the central maximum on the screen kept 2 ~m from the slit is :

Step-by-step solution

The width of the central maximum in a single slit diffraction pattern is given by the formula w = 2 D a , where is the wavelength of light, D is the distance of the screen from the slit, and a is the width of the slit. Given values are: = 6400 10⁻¹⁰ m = 6.4 10⁻⁷ m D = 2 m a = 2 mm = 2 10⁻³ m Substituting these values into the formula: w = 2 (6.4 10⁻⁷ m ) (2 m ) 2 10⁻³ m w = 25.6 10⁻⁷ 2 10⁻³ m w = 12.8 10⁻⁴ m w = 1.28 10⁻³ m = 1.28 mm Answer: 1.28 mm