In Young's double slit experiment, the two slits are separated by 0.2 ~mm and they are 1 ~m from the screen. The wavelength of the light used is 500 ~nm . The distance between 6th maxima and 10 th minima on the screen is closest to

Step-by-step solution

Given parameters are slit separation d = 0.2 ~mm = 0.2 10⁻³ ~m , distance to screen D = 1 ~m , and wavelength = 500 ~nm = 500 10⁻⁹ ~m . The position of the n -th maxima is given by y_ n, max = n D d . For the 6th maxima, n = 6 . y_ 6, max = 6 1 500 10⁻⁹ 0.2 10⁻³ = 6 2.5 10⁻³ ~m = 15 10⁻³ ~m = 15 ~mm . The position of the m -th minima is given by y_ m, min = (m - 0.5) D d . For the 10th minima, m = 10 . y_ 10, min = (10 - 0.5) 1 500 10⁻⁹ 0.2 10⁻³ = 9.5 2.5 10⁻³ ~m = 23.75 10⁻³ ~m = 23.75 ~mm . The distance between t