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In Young's double slit experiment, the fringe width is found to be 0.4 ~mm . If the whole apparatus is immersed in a liquid of refractive index 4 3 without changing geometrical arrangement, the new fringe width will be

Options

  1. A0.45 mm
  2. B0.4 mm
  3. C0.53 mm
  4. D0.30 mm

Correct answer

D. 0.30 mm

Step-by-step solution

The fringe width in Young's double slit experiment is given by the formula = D d , where is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the two slits. When the apparatus is immersed in a liquid of refractive index , the wavelength of light changes to ' = . The new fringe width ' becomes ' = ' D d = D d = . Given = 0.4 mm and = 4 3 , we calculate the new fringe width as ' = 0.4 4/3 = 0.4 3 4 = 0.3 mm . Answer: 0.30 mm

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