COMEDK2021PhysicsWave Optics
In Young's double slit experiment with sodium vapour lamp of wavelength 589 ~nm and slit 0.589 ~mm apart, the half angular width of the central maxima is
Options
- A⁻¹(0.01)
- B⁻¹(0.0001)
- C⁻¹(0.001)
- D⁻¹(0.1)
Correct answer
C. ⁻¹(0.001)
Step-by-step solution
In Young's double slit experiment, the angular width of the central maxima is defined by the position of the first minima on either side of the central point. The condition for the first minima in a double slit interference pattern is given by d = , where d is the slit separation and is the wavelength of light. Given values are = 589 nm = 589 10⁻⁹ m and d = 0.589 mm = 0.589 10⁻³ m = 589 10⁻⁶ m . Substituting these values into the condition for the first minima: = d = 589 10⁻⁹ 589 10⁻⁶ = 10⁻³ = 0.001 Therefore, the