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COMEDK2018PhysicsWave Optics

The maximum number of possible interference maxima when slit separation is equal to 4 times the wavelength of light used in a double slit experiment is

Options

  1. A9
  2. B8
  3. C4

Correct answer

3

Step-by-step solution

In double slit experiment, for possible interference maxima on the screen is given as aligned d &=n Given, slit width, d &=4 4 &=n 4 &=n aligned Since, maximum value of =1 For maximum number of possible interference maxima, aligned & & 4 1 &=n & & n &=4 i.e., & & n &=0,1,2,3 aligned Maximum number of possible maxima will be 7 i.e. 0, 1, 2, 3 Hence, no option is correct.

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