In a Fraunhofer diffraction experiment at a single slit using a light of wavelength 400 ~nm , the first minimum is formed at an angle of 30^ . The direction of the first secondary maximum is given by

Step-by-step solution

Given, wavelength of used light, =400 ~nm For minima in Fraunhofer diffraction, d 30^ =1 400 d=800 ~nm For maxima in diffraction, d =(2 n+1) 2 For first maxima n=0 array ll & d =(0+1) 2 & d = 2 & 800 = 400 2 & = 1 4 & = ⁻¹ ( 1 4 ) array