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COMEDK2017PhysicsWave Optics

A single slit of width a is illuminated by violet light of wavelength 400 ~nm and the width of the diffraction pattern is measured as y . When half of the slit width is covered and illuminated by yellow light of wavelength 600 ~nm , the width of the diffraction pattern is

Options

  1. Athe pattern vanishes and the width is zero
  2. By 3
  3. C3 y
  4. DNone of the above

Correct answer

C. 3 y

Step-by-step solution

Given, In first case, Wavelength of violet light, ₁=400 ~nm We know that, width of the diffraction pattern is given as aligned & =y= 2 D ₁ d & y= 2 D ₁ d = 2 D 400 d aligned y= 800 D d ...(i) In the second case, aligned ₂ &=600 ~nm , d^ = d 2 y^ &= 2 D ^ d^ = 2 D 600 d 2 &=2400 D d =3 800 D d [from Eq. (i)] &=3 y aligned

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