COMEDK2014PhysicsWave Optics
A source of light of wavelength 5000 Å is placed at one end of a table 2 ~m long and 5 ~mm above its flat well polished top. The fringe width of the interference bands seen on a screen located at the end of the table is
Options
- A2 10⁻⁵ ~m
- B2 10⁻⁴ ~m
- C2 10⁻³ ~m
- D2 10⁻² ~m
Correct answer
B. 2 10⁻⁴ ~m
Step-by-step solution
Given, wavelength of light used, aligned &=5000 Å=5 10⁻⁷ ~m D &=2 ~m d &=5 ~mm =5 10⁻³ ~m aligned Fringe width, = D d = 2 5 10⁻⁷ 5 10⁻³ =2 10⁻⁴ ~m