A motor cyclist starts from the top of an inclined plane of height h to go around a globe of death trap of radius r. The ratio of minimum height 'h' of the inclined plane to the radius 'r' of the death globe in order to go around the death globe successfully is

Step-by-step solution

By conservation of mechanical energy, the velocity of the motorcyclist at the bottom of the inclined plane is given by mgh = 1 2 mv^2 v = 2gh To successfully complete the vertical circular loop (globe of death) of radius r , the minimum velocity required at the lowest point is v 5gr For the minimum height h , we equate the velocities: 2gh = 5gr 2gh = 5gr h r = 5 2 The ratio of the minimum height to the radius is 5:2 . Answer: 5:2