COMEDK2025PhysicsWork, Power and EnergyActual
A body of mass 0.5 kg is dropped from a height of 2 m on the top of the spring of length 0.6 m , fixed vertically on the horizontal table. If the spring is depressed by a distance of 10 cm , then what will be the spring constant of the spring? g=10 ~ms ⁻²
Options
- A200 Nm ⁻¹
- B150 Nm ⁻¹
- C1500 Nm ⁻¹
- D2000 Nm ⁻¹
Correct answer
C. 1500 Nm ⁻¹
Step-by-step solution
Total height fallen: h = (2 - 0.6) + 0.1 = 1.5 m By energy conservation: mgh = 1 2 kx^2 0.5 10 1.5 = 1 2 k (0.1)^2 7.5 = 0.005k k = 1500 Nm⁻¹