COMEDK2024PhysicsWork, Power and EnergyActual
An object of mass 3 kg moves due to an applied constant force such that its position along X axis is given by x = t^ 2 3 where x is in meters and t in seconds. The work done in 1 second is
Options
- A1 J
- B2 J
- C6 J
- D2 3 J
Correct answer
D. 2 3 J
Step-by-step solution
x = t^2 3 v = dx dt = 2t 3 At t = 0 : v_i = 0 , at t = 1 s: v_f = 2 3 m/s By work-energy theorem: W = 1 2 mv_f^2 - 1 2 mv_i^2 = 1 2 3 ( 2 3 )^2 - 0 = 3 2 4 9 = 2 3 J