A particle is projected at an angle 30^ with horizontal having kinetic energy K . The kinetic energy of the particle at highest point is.

Step-by-step solution

Initial kinetic energy is Final kinetic energy is array rlrl K^ & = 1 2 m v^2= 1 2 m (u 30^ )^2 & [ v=u 30^ ] & = 3 4 ( 1 2 m u^2 )= 3 4 K & & [From Eq. (i)] array