IAT IISER2019MathematicsComplex Number
Let 1, ₂, ₃, , _n be the roots of the equation x^n=1 , for n 3 . Then, the sum 1 2- ₂ + 1 2- ₃ + + 1 2- _n equals to
Options
- A1+(n-2) 2^n 2^n-1 .
- B1+n 2^ n-1 -2^n 2^n-1 .
- C1+n 2^ n-1 -2^n 2^ n-1 +1 .
- D1+(n-1) 2^n-2^ n-1 2^ n-1 +1 .
Correct answer
B. 1+n 2^ n-1 -2^n 2^n-1 .
Step-by-step solution
No solution available.