Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced2026MathematicsArea Under CurvesActual

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection of the curves C₁ and C₂ . Suppose that ₁, ₂, , _n [0, 10 ] are the x -coordinates of the points of intersection of the curves C₁ and C₂ such that ₁ Question: Let be the area of the region enclosed between the curves C₁ , C₂ , and the lines

Correct answer

0

Step-by-step solution

To find the points of intersection of the curves C₁ and C₂ , we equate their equations: e^ -x = e^ -x ( x + x) Since e^ -x 0 , we have: x + x = 1 2 (x + 4 ) = 1 (x + 4 ) = 1 2 The general solution is x + 4 = 2k + 4 or x + 4 = 2k + 3 4 for any integer k . Thus, x = 2k or x = 2k + 2 . For x [0, 10 ] , the first four points of intersection are: ₁ = 0 ₂ = 2 ₃ = 2 ₄ = 2 + 2 = 5 2 The area enclosed between the curves from x = ₁ to x = ₄ is given by: = ₀^ 5 2 |e^ -x ( x + x - 1)| dx We analyze the sign of x + x - 1 in the

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026Let P₁: y=4 x² and P₂: y=x²+27 be two parabolas. If the area of the bounded region enclosed between P₁ and P₂ is six times the area of the bounded region enclosed between the line 2026 Full Area Under Curves list All JEE Advanced PYQs