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JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Mathematics
Chapter
Permutation and Combination

JEE Advanced 2025 · Paper 1 · Mathematics · Permutation and Combination

Let S be the set of all seven-digit numbers that can be formed...

Let SS be the set of all seven-digit numbers that can be formed using the digits 0,1 and 2 . For example, 2210222 is in SS, but 0210222 is NOT in SS. Then the number of elements xx in SS such that at least one the digits 0 and 1 appears exactly twice in xx, is equal to ______.

Correct answer

0

Step-by-step solution

Let A→\mathrm{A} \rightarrow " 0 " appear exactly twice. and B→"1"\mathrm{B} \rightarrow " 1 " appear exactly twice. ∴A∩B→\therefore \mathrm{A} \cap \mathrm{B} \rightarrow " 0 " and " 1 " both appears exactly twice. \mathrm{n}(\mathrm{A})=-\underbrace{-------} ={ }_{\text{placing zero }^6 \mathrm{C}_2(1)(2)^5=\frac{6 \times 5}{2} \times 2^5=480 for n(B)\mathrm{n}(\mathrm{B}) C-I : 11 at first place 1‾−−−−−−−⏟ Number of  ways = placing 16C1(1)(2)5=192\underline{1}\underbrace{-------} \text{ Number\text{ of } ways }=\underset{\text{ placing } 1}{} \mathrm{}^6{C}_1(1)(2)^5=192 C-II : 2 at first place 2‾−−−−−−−⏟\underline{2}\underbrace{-------} Number of ways =6C2(1)(2)4 placing 1=6×52×24=240n(B)=240+192=\underset{\text{ placing } 1}{{ }^6 \mathrm{C}_2(1)(2)^4}=\frac{6 \times 5}{2} \times 2^4=240 n(B)=240+192 for n(A∩B)‾−−−−−−−⏟\mathrm{n}(\mathrm{A} \cap \mathrm{B}) \underline{}\underbrace{-------} for n(A∩B)=6C2(1) placing zero ×5C2(1) placing 1×(1) 2at rest places 1=6×52×5×42=150\mathrm{n}(\mathrm{A} \cap \mathrm{B})=\underset{\text{ placing zero }}{{ }^6 \mathrm{C}_2(1)} \times \underset{\text{ placing } 1}{{ }^5 \mathrm{C}_2(1)} \times \underset{\text{ 2at rest places } 1}{(1)} =\frac{6 \times 5}{2} \times \frac{5 \times 4}{2}=150∴n(A∪B)=n(A)+n(B)−n(A∩B)=480+(192+240)−150=762\begin{aligned} & \therefore \mathrm{n}(\mathrm{A} \cup \mathrm{B})=\mathrm{n}(\mathrm{A})+\mathrm{n}(\mathrm{B})-\mathrm{n}(\mathrm{A} \cap \mathrm{B}) \\ & =480+(192+240)-150 \\ & =762\end{aligned}$$
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