JEE Advanced 2024Paper 1
- Exam
- JEE Advanced
- Year
- 2024
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Permutation and Combination
JEE Advanced 2024 · Paper 1 · Mathematics · Permutation and Combination
A group of 9 students, s_1, ~s_2, , s_9 , is to be divided to from...
A group of 9 students, , is to be divided to from three teams , and of sizes 2,3 , and 4 , respectively. Suppose that cannot be selected for the team , and cannot be selected for the team Y. Then the number of ways to from such teams, is
Correct answer
665
Step-by-step solution
C-i) when does not contain , but contains
(\underset{\text{(for }x)}{{ }^7 C_1} \times \underset{\text{(for }y,z)}{\frac{7!}{3!4!}}=245)
C-ii) When does not contain and does not contain i.e. (\underset{\text{(for }x)}{{ }^{7} \mathrm{C}_2} \times \underset{\text{(for }y,z)}{\frac{6!}{3!3!}}=420)
so total No. of ways