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JEE Advanced 2024Paper 1
Exam
JEE Advanced
Year
2024
Paper
Paper 1
Subject
Mathematics
Chapter
Permutation and Combination

JEE Advanced 2024 · Paper 1 · Mathematics · Permutation and Combination

A group of 9 students, s_1, ~s_2, , s_9 , is to be divided to from...

A group of 9 students, s1, s2,……,s9\mathrm{s}_1, \mathrm{~s}_2, \ldots \ldots, \mathrm{s}_9, is to be divided to from three teams X,Y\mathrm{X}, \mathrm{Y}, and Z\mathrm{Z} of sizes 2,3 , and 4 , respectively. Suppose that s1s_1 cannot be selected for the team X\mathrm{X}, and s2\mathrm{s}_2 cannot be selected for the team Y. Then the number of ways to from such teams, is

Correct answer

665

Step-by-step solution

xyz234\begin{array}{ccc}\mathrm{x} & \mathrm{y} & \mathrm{z} \\ 2 & 3 & 4 \end{array} C-i) when xx does not contain S1\mathrm{S}_1, but contains S2\mathrm{S}_2 (\underset{\text{(for }x)}{{ }^7 C_1} \times \underset{\text{(for }y,z)}{\frac{7!}{3!4!}}=245) C-ii) When x\mathrm{x} does not contain S1, S2\mathrm{S}_1, \mathrm{~S}_2 and y\mathrm{y} does not contain S2\mathrm{S}_2 i.e. (\underset{\text{(for }x)}{{ }^{7} \mathrm{C}_2} \times \underset{\text{(for }y,z)}{\frac{6!}{3!3!}}=420) so total No. of ways 665665
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