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JEE Advanced 2020Paper 2
Exam
JEE Advanced
Year
2020
Paper
Paper 2
Subject
Mathematics
Chapter
Permutation and Combination

JEE Advanced 2020 · Paper 2 · Mathematics · Permutation and Combination

In a hotel, four rooms are available. Six persons are to be...

In a hotel, four rooms are available. Six persons are to be accommodated in these four rooms in such a way that each of these rooms contains at least one person and at most two persons. Then the number of all possible ways in which this can be done is_____

Correct answer

0

Step-by-step solution

66 persons can be distributed in 44 rooms in the group of (1,1,2,2)\left(1, 1, 2, 2\right) by 6!(1!1!2!2!)(2!2!)×4!=720×2416=1080\dfrac{6 !}{\left(1 ! 1 ! 2 ! 2 !\right)\left(2 ! 2 !\right)} \times 4 != \dfrac{720 \times 24}{16} = 1080.

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