JEE Advanced 2018Paper 2
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Permutation and Combination
JEE Advanced 2018 · Paper 2 · Mathematics · Permutation and Combination
In a high school, a committee has to be formed from a group of 6...
In a high school, a committee has to be formed from a group of boys
and girls .
(i) Let be the total number of ways in which the committee can be formed such that the committee has members, having exactly boys and girls.
(ii) Let be the total number of ways in which the committee can be formed such that the committee has at least members, and having an equal number of boys and girls.
(iii) Let be the total number of ways in which the committee can be formed such that the committee has members, at least of them being girls.
(iv) Let be the total number of ways in which the committee can be formed such that the committee has members, having at least girls and such that both and are NOT in the committee together.
The correct option is:
and girls .
(i) Let be the total number of ways in which the committee can be formed such that the committee has members, having exactly boys and girls.
(ii) Let be the total number of ways in which the committee can be formed such that the committee has at least members, and having an equal number of boys and girls.
(iii) Let be the total number of ways in which the committee can be formed such that the committee has members, at least of them being girls.
(iv) Let be the total number of ways in which the committee can be formed such that the committee has members, having at least girls and such that both and are NOT in the committee together.
| LIST-I | LIST-II |
| A. The value of is | P. |
| B. The value of is | Q. |
| C. The value of is | R. |
| D. The value of is | S. |
| T. | |
| U. |
Options
- Aa-s;b-u;c-t;d-q;
- Ba-u;b-t;c-q;d-p;
- Ca-t;b-r;c-s;d-p;
- Da-t;b-r;c-q;d-p;
Correct answer
A. a-s;b-u;c-t;d-q;
Step-by-step solution
\left(1\right){\alpha}_{1} = \left(\right)\left(\right) = 200
So
\left(2\right){\alpha}_{2} = \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right)
= \left(\right) - 1 = 461
So
\left(3\right){\alpha}_{3} = \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right)
= \left(\right) - \left(\right)\left(\right) - \left(\right)\left(\right) = 381
So
\left(4\right){\alpha}_{2} = \left(\right)\left(\right) - \left(\right)\left(\right) + \left(\right)\left(\right) - \left(\right)\left(\right) + \left(\right) = 189
So
So
\left(2\right){\alpha}_{2} = \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right)
= \left(\right) - 1 = 461
So
\left(3\right){\alpha}_{3} = \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right) + \left(\right)\left(\right)
= \left(\right) - \left(\right)\left(\right) - \left(\right)\left(\right) = 381
So
\left(4\right){\alpha}_{2} = \left(\right)\left(\right) - \left(\right)\left(\right) + \left(\right)\left(\right) - \left(\right)\left(\right) + \left(\right) = 189
So